Python explanation (Edabit // Fizz Buzz Interview Question)

Hello!

Today is going to be Python Explanation!

🐍: ME?😍

Leo618 : Uh, no...😓

🐍 : Oh.....😒

Leo618 : Sorry, uh..... Never mind.😅

 The question is this!

Create a function that takes a number as an argument and returns "Fizz", "Buzz" or "FizzBuzz".

• If the number is a multiple of 3 the output should be "Fizz".
• If the number given is a multiple of 5, the output should be "Buzz".
• If the number given is a multiple of both 3 and 5, the output should be "FizzBuzz".
• If the number is not a multiple of either 3 or 5, the number should be output on its own as shown in the examples below.
• The output should always be a string even if it is not a multiple of 3 or 5.

Examples

fizz_buzz(3) ➞ "Fizz"

fizz_buzz(5) ➞ "Buzz"

fizz_buzz(15) ➞ "FizzBuzz"

fizz_buzz(4) ➞ "4"

So, this is the solved code!!

def fizz_buzz(num):

if num % 3 == 0 and num % 5 == 0:

return "FizzBuzz"

if num % 3 == 0:

return "Fizz"

if num % 5 == 0:

return "Buzz"

else:

return str(num)

I'll change the font...😎(WHY!)

so, Let's see the code.

The first if is when the number is a multiple of either 3 or 5.

If the answer is 0 when the number ModulO with 3, AND when the answer is 0 when the number Modulo with 5.

Then, we return "FizzBuzz"!

The second if  is when the number is a muLtiple of 3.

If the Answer is 0 when the number Modulo with 3, then we return "Fizz"!

The third if is when the number is a multiple of 5.

If the answer is 0 when the number modulo with 5, then we return "BUZZ"!

Lastly, when the number is not a multiple of 3 or 5, Return the number Stringed.

How was it?

It was really easy!

Piece of a cake!

Bye!!!